x^2=4x+95

Solution for x^2=4x+95 equation:

x^2=4x+95

We move all terms to the left:

x^2-(4x+95)=0

We get rid of parentheses

x^2-4x-95=0

a = 1; b = -4; c = -95;
Δ = b2-4ac
Δ = -42-4·1·(-95)
Δ = 396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{396}=\sqrt{36*11}=\sqrt{36}*\sqrt{11}=6\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6\sqrt{11}}{2*1}=\frac{4-6\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6\sqrt{11}}{2*1}=\frac{4+6\sqrt{11}}{2}
$